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A freezer has a coefficient of performance of 6.30. The freezer is advertised as using 466 kW-h/yr?

A freezer has a coefficient of performance (COP) of 6.30 and is advertised as using 466 kWh per year.

Note: One kilowatt-hour (kWh) represents the amount of energy consumed by a 1-kW appliance operating for one hour.

(a) On average, how much energy does the freezer consume in a single day? Please provide your answer in joules (J).

(b) On average, how much energy does the freezer remove from the refrigerator in a single day? Please provide your answer in joules (J).

(c) What is the maximum mass of water at 17.1°C that the freezer could freeze in a single day? (The latent heat of fusion of water is 3.33 x 10^5 J/kg, and its specific heat is 4186 J/kg·°C.) Please provide your answer in kilograms (kg).

1 Answers

A
Anonymous

Jan 26, 2025

(a) consumption per day = 466/365 = 1.28 kw-hr

(b) By COP(cooling) = Q/W

=>Q = W x COP

=>Q = 1280 x 6.30 = 8040 J

(c) By Q = ms∆t + mL

=>8040 = m x 4186 x (100 – 17.1) + m x 333000

=>8040 = 680019.4m

=>m = 0.01182 kg

=>m = 11.83 gm

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