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Kelsie Sawayn

Feb 20, 2025

A hand exerciser utilizes a coiled spring?

A force of 89.0 N is required to compress the spring by 0.0191 m. Determine the force needed to compress the spring by 0.0508 m.
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Hermina Ferry

Feb 20, 2025

F = kx89.0 N = k * 0.0191 mk = 89.0 / 0.0191 = 4660 N/m Force to compress the spring by 0.0508 m = kx = 4660 N/m * 0.0508 N/M = 236.7 N... Show More
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Hermina Ferry

Feb 20, 2025

First, find the spring constant: F = k × x (88.3 N) = k × (0.0183 m) k = 4825 N/m Now find the force needed: F = k × x F = (4825 N/m) × (0.0471 m) F = 227 N... Show More
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