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A

Anonymous

Jan 16, 2025

You need to prepare 2.00 L of 0.100 M Na2CO3 solution. The best procedure is to weigh out…?

To prepare 2.00 L of a 0.100 M Na2CO3 solution, which of the following procedures is correct?

a. Weigh out 10.6 g of Na2CO3 and add 2.00 L of water to it.
b. Weigh out 21.2 g of Na2CO3 and add 2.00 L of water to it.
c. Weigh out 10.6 g of Na2CO3 and add water until the final solution reaches a volume of 2.00 L.
d. Weigh out 21.2 g of Na2CO3 and add water until the final solution reaches a volume of 2.00 L.

2 Answers

A
Anonymous

Jan 29, 2025

Using the Conc and the vol you can find out how many moles you need.

moles = C x V

moles = 0.100 mol/L x 2.00 L = 0.200 mol

Now convert the 0.200 moles back into mass by using mass = moles x molar mass

mass = 0.200 mol x 105.99 g/mol = 21.198 grams.

A
Anonymous

Feb 16, 2025

molar mass of Na2CO3 = 106 g/mol

find out how many moles of Na2CO3 you need:

0.1 mol/L * 2 L = 0.2 mol

multiply by molar mass to get a mass in grams:

0.2 mol * 106 g/mol = 21.2 g

you would dissolve this in enough water so that the final volume is 2 L; you can't just add it to 2 L of water because the solute may occupy some volume such that the final volume would be more than 2 L and the concentration wouldn't be exactly 0.1 M.

so the answer is D

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