An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm3. according to the data, to what number of significant figures

Question

An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm³. Based on this data, to what number of significant figures should the calculated volume of the aluminum sample be expressed?

Anonymous · Accepted Answer

Not 100% sure, but I'd have to say this:When rounding for sig figs, you look at the other numbers in your calculation and see which one has the least amount of sig figs. This number is 2.70. (3 sig figs). So, you round to 3 significant figures in your calculation.Hope this helped!

Anonymous · Answer

Answer : The volume of aluminium sample should be Explanation :Density : It is defined as the mass contained per unit volume.Formula used :Given : Mass of aluminum = 80.01 gDensity of aluminium = Now put all the given values in the above formula, we get :Therefore, the volume of aluminium sample should be

Anonymous · Answer

C. 3Explanation:To determine the number of significant figures use this memory aid:  If the decimal is Absent count from the Atlantic (right side).  If the decimal is Present count from the Pacific (left side).   Start counting at the first non-zero digit.The result of a calculation can only contain the lowest number of significant figures given in the problem.  2.70 has 3 significant figures.

Anonymous · Answer

The answer is (3) 3. The calculation rule of significant figures is when multiplication and division, the significant figures of result is equal to the least of the numbers involved. The significant figure of 2.70 and 80.01 is 3 and 4.

Anonymous

An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm3. according to the data, to what number of significant figures

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