An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 300 N.?
An archer pulls her bowstring back by 0.400 m, exerting a force that increases uniformly from 0 N to 300 N. (a) What is the equivalent spring constant of the bow, expressed in N/m? (b) How much work is done in pulling the bow, expressed in joules (J)?
5 Answers
The spring constant would be 300 divided by .4 or 750 N/m
For the work use the average force 0 + 300 divided by 2 = 150 N
W = F x d = 150 x .4 = 60 J
Feb 20, 2025
historically inaccurate. ?
but:
F = k (delta x)
300 = .4k
k=120 N/m
W = F(x)(cos theta)
W = 300 (.4) (1)
W = 120 J
I think this is right….
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