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An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 300 N.?

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 300 N. (a) What is the equivalent spring constant of the bow?N/m(b) How much work is done in pulling the bow?J
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5 Answers

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Anya Stehr

Feb 20, 2025

The spring constant would be 300 divided by .4 or 750 N/mFor the work use the average force 0 + 300 divided by 2 = 150 NW = F x d = 150 x .4 = 60 J... Show More
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A
Anya Stehr

Feb 20, 2025

historically inaccurate. 😀but:F = k (delta x)300 = .4kk=120 N/mW = F(x)(cos theta)W = 300 (.4) (1)W = 120 JI think this is right….... Show More
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A
Anya Stehr

Feb 20, 2025

a) f=kx 300=0.4kb) w= 1/2 kx^2those are what you need for workingaverage blah blah blah is bull ****.... Show More
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