An auto mechanic spills 67 mL of 2.6 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 1.3 M NaHCO3 must be poured

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An auto mechanic spills 67 mL of 2.6 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 1.3 M NaHCO3 must be poured on the spill to react completely with the sulfuric acid?

Anya Stehr · Accepted Answer

2 NaHCO₃ + H₂SO₄  →  Na₂SO₄ + 2 H₂O + 2 CO₂we are supposed to find the volume of a 1.3 M solution, which has twice the number of moles as H2SO4 in 67 mL of 2.6M solution; since we need 2 moles of NaHCO₃ to react with 1 mole Number of Moles of H₂SO₄ Spilled:Since the molarity is 2.6M, We have 2.6 moles in 1000 mL of the solutionWe have 0.26 moles in 100 mL of the solutionMoles in 67mL: Since we have 0.26 moles in 100 mLto get the number of moles in 67 mL, we have to find 67% of 0.26 Moles in 67 mL = 67 * 26 / 10000 = 0.1742 moles OR 0.17 moles (approx)Volume of NaHCO₃ which has (0.17*2) = 0.34 moles:The molarity of NaHCO₃ is 1.3 M, So:We have 1.3 moles in 1000 mLWe have 0.13 moles in 100 mLTo get the volume required, we have to find what percent of 0.13 is 0.17:x*13/100 = 3413x = 3400x = 3400 / 13x = 261.5 %since 261.5% of 0.13 is 0.34So, volume which contains 0.34 moles = 261.5% of the volume that contains 0.13 molesVolume = 261.5% * 100Volume = 261.5 mL

Anya Stehr · Answer

answeridentity;

Anya Stehr · Answer

it has both hydrogen and oxygen

Karelle Stoltenberg

An auto mechanic spills 67 mL of 2.6 M H2SO4 solution from a rebuilt auto battery. How many milliliters of 1.3 M NaHCO3 must be poured

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