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Sigrid O'Kon

Feb 20, 2025

Calculate ΔH for formation of 0.480mol of AgCl by this reaction.?

Ag+(aq)+Cl−(aq)→AgCl(s)ΔH=−65.5kJPlease explain how to do this as well as.. Calculate ΔH for the formation of 8.00g of AgCl.and Calculate ΔH when 9.21×10−4mol of AgCl dissolves in water.

1 Answers

(0.480 mol AgCl) × (−65.5 kJ/mol AgCl) = −31.44 kJ(8.00 g AgCl) / (143.3212 g AgCl/mol) × (−65.5 kJ/mol AgCl) = −3.66 kJ (9.21 × 10^−4 mol AgCl) × (+65.5 kJ/mol) = 0.0603255 kJ = +60.3 J[Note that the sign on ΔH changed because the dissolving of AgCl in water is represented by the backwards form of the given equation.]... Show More

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