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Miss Veda Hane

Jan 21, 2025

Calculate Kc for the reaction below?

I am seeking assistance in calculating the equilibrium constant (Kc) for the following reaction at 298 K:

I2 (g) ⇌ 2I (g)

I have a given value for the equilibrium constant in terms of pressure, Kp = 6.26 × 10^-22. Could someone guide me through the process of converting Kp to Kc for this reaction? Thank you!

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2 Answers

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Anonymous

Jan 28, 2025

Had the exact problem in Mastering Chem!!

So the formula that you use is Kp = Kc(RT)^Δn

Since you’re working with a gas, use the ideal gas law constant: R = 0.08205

T is already in Kelvin

For Δn, subtract the number of moles of your product from your reactant side: 2-1=1

Then plug it all in: (6.26*10^-22) = Kc (0.08205 * 298)^1

6.26*10^-22 = Kc*24.4509

Kc = 2.56*10^ -23

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A
Anonymous

Feb 20, 2025

For situation #2, use the equation Kp=Kc(RT)^delta n by using fact you have 2 moles on the two aspects of the equation, delta n would be 0, subsequently making your equation for Kp=(80 one.9)/(.08206*298)^0) answer is 80 one.9

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Chemistry

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Chemistry Equilibrium Constant Kc

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