Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal places

Question

Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal places and include the appropriate units.

Mr. Toni Zulauf Sr. · Accepted Answer

0.00649MThe question is incomplete,You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012With that you can solve the question following these steps" 1) First ionization:H₂SO₄(aq) --> H⁺ (aq) + HSO₄⁻ (aq)Under the fully ionization assumption the concentration of HSO4- is the same of the acid = 0.01 M2) Second ionizationHSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012 Do the mass balance:        HSO₄⁻ (aq)        H⁺        SO₄²⁻        0.01 M  - x          x            x Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]=> Ka₂ = (x²) / (0.01 - x) = 0.0123) Solve the equation:x² = 0.012(0.01 - x) = 0.00012 - 0.012xx² + 0.012x - 0.0012 = 0Using the quadratic formula: x = 0.00649 So, the requested concentratioN is [SO₄²⁻] = 0.00649M

Mr. Toni Zulauf Sr. · Answer

The concentration of sulfate ions is 0.0100 M.Explanation:Concentration of sulfuric acid =0.0100 M1 mol of sulfuric acid gives 2 mole of ion and 1mole of ion.The concentration of sulfate ions is 0.0100 M.

Mr. Toni Zulauf Sr. · Answer

The concentration of sulfate ions in the solution is 0.010 MExplanation:The chemical formula of sulfuric acid solution is We are given:Concentration of sulfuric acid = 0.010 MThe chemical equation for the ionization of sulfuric acid follows:1 mole of sulfuric acid produces 2 moles of hydrogen ions and 1 mole of sulfate ions Concentration of sulfate ions = (1 × 0.010) = 0.010 MHence, the concentration of sulfate ions in the solution is 0.010 M

Sigrid O'Kon

Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal places

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