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A

Anonymous

Feb 11, 2025

Calculate the mass in grams of $700 billion worth of gold.?

In 2009, one of the U.S. government’s bailout packages amounted to $700 billion, at a time when gold was valued at $800 per ounce (or $28.20 per gram).

  1. Calculate the mass, in grams, of $700 billion worth of gold.
  2. If this quantity of gold were shaped into a cube, what would be the length of each side?

3 Answers

I’m using the American billion… Since you used $

Therefore 700 Billion dollars = 70 x 10^10

Therefore (70 x 10^10)/28.80 = 2.4822…. x 10^10 grams

The density of Gold (sourced from wikipedia) is 19.30 grams per cm^3

Therefore since density = mass/volume

Volume = mass/density

Therefore volume = (2.4822…. x 10^10)/19.3 = 1286150002 cm^3

Therefore one side of the cube would be the cube root of 1286150002 which is 35862.93354 cm or simply 360 metres to 3 sig fig.

A
Anonymous

Jan 02, 2025

1. Divide $700 billion by $28.20.

2. For this, you need to know the density of gold, in grams per cubic centimeter (google it). Then you can get the volume of the hypothetical cube as:

Volume (in cubic centimeters) = (number of grams) / density

(You got the “number of grams” part in question #1).

Now if you have a cube with a known volume, its side equals:

length of side = cube root of volume. (use a calculator)

If the volume is in “cubic centimeters”, the length will come out in “centimeters”.

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