Calculate the mass in grams of $700 billion worth of gold.?

Question

In 2009, one of the U.S. government’s bailout packages was $700 billion when gold was worth $800 per ounce ($28.20 per gram).1. Calculate the mass in grams of $700 billion worth of gold. 2. If this amount of gold were in the shape of a cube, how long would each of its sides be?

Mr. Toni Zulauf Sr. · Accepted Answer

I’m using the American billion… Since you used $Therefore 700 Billion dollars = 70 x 10^10 Therefore (70 x 10^10)/28.80 = 2.4822…. x 10^10 gramsThe density of Gold (sourced from wikipedia) is 19.30 grams per cm^3Therefore since density = mass/volumeVolume = mass/densityTherefore volume = (2.4822…. x 10^10)/19.3 = 1286150002 cm^3Therefore one side of the cube would be the cube root of 1286150002 which is 35862.93354 cm or simply 360 metres to 3 sig fig.

Mr. Toni Zulauf Sr. · Answer

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Mr. Toni Zulauf Sr. · Answer

1. Divide $700 billion by $28.20.2. For this, you need to know the density of gold, in grams per cubic centimeter (google it). Then you can get the volume of the hypothetical cube as:Volume (in cubic centimeters) = (number of grams) / density(You got the “number of grams” part in question #1).Now if you have a cube with a known volume, its side equals:length of side = cube root of volume. (use a calculator)If the volume is in “cubic centimeters”, the length will come out in “centimeters”.

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Calculate the mass in grams of $700 billion worth of gold.?

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