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Anonymous

Dec 03, 2024

Calculate the molality of the solution. (assume a density of 1.08 g/ml for the solution.)an aqueous nacl solution is made using 140

Calculate the molality of the solution using 140 g of NaCl diluted to a total volume of 1.20 L of solution. Assume the density of the solution is 1.08 g/mL.

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Uriah Romaguera

Jan 15, 2025

molality is moles solute / kg of solvent  moles of NaCl = mass / molar mass molar mass NaCl = 58.44 g/mol moles NaCl = 140 g / 58.44 g/mol = 2.40 mol NaCl  The total volume of the solution is 1.2L or 1200 ml The density of the solution is 1.08 g/ml   Therefore the total mass of the solution is 1.08 g/ml x 1200ml = 1296 g  But there are140 g of NaCl in this solution  So mass H2O = 1296 g - 140 g = 1156 g = 1.156 kg  molality = moles solute/ kg solvent = 2.40 mol / 1.156 kg = 2.08 molal
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Anonymous

Jan 11, 2025

i think it is true since you can test the answer and can use observations to complete it.
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