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Anonymous

Dec 11, 2024

Chords AB and CD intersect at point E, AE =10, EB=4, and CE =8. Therefore, ED=

Chords AB and CD intersect at point E, where AE measures 10 units, EB measures 4 units, and CE measures 8 units. What is the length of segment ED?

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6 Answers

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Anonymous

Feb 12, 2025

5Step-by-step explanation:5 is correct, since (CE)(ED) = (AE)(EB).
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A
Anonymous

Nov 19, 2024

5Step-by-step explanation:5 is correct, since (CE)(ED) = (AE)(EB).
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Answer with explanation:It is given that two chords  AB and CD intersect at point E.  Also, A E= 10, E B=4 , CE=8So, By Intersecting chord Theorem⇒A E × E B = CE × E D⇒10 × 4= 8 × ED⇒ 40 =8× DEDividing both sides by , 8 we getDE= 5 unitOption: B, DE=5 unit
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Anonymous

Feb 03, 2025

So here is how we are going to find out what is ED. Based on the given figure, it states that AE is 10, and EB is 4 and CE are 8.So, (AE/CE)=(ED/EB)10/8 = ED/4 <
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Abbie Zemlak

Nov 24, 2024

So here is how we are going to find out what is ED. Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.So, (AE/CE)=(ED/EB)10/8 = ED/4 <
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