Determining the velocity of a charged particle physics help!?

Question

i am having problems getting the right answer to this problem any help would be appreciated. A particle with a charge of = -5.80 nC is moving in a uniform magnetic field of B=( -1.23 T) z^ . The magnetic force on the particle is measured to be F= −7.60×10−7 N) y^calculate the x component of the velocity of the particle is m/s?can Vy and Vz, the y and z components of velocity be determined by measuring the force?

Prof. Clark Walter · Accepted Answer

F = q(v x B) (x is vector cross product)F(y) = q(v(z)B(x) - v(x)B(z))Since B(x) = 0, v(z) cannot be determined from F(y), andF(y) = -qv(x)B(z) ==> v(x) = -F(y)/(qB(z))I get v(x) = +106.5321 m/s

Prof. Clark Walter · Answer

For the best answers, search on this site https://shorturl.im/qS2unE = σ /εₒ Upward force on the proton = Ee and the downward force = mg Net acceleration upward = [Ee-mg] /m In the vertical direction the distance moved = 0.01 m Time of travel = 0.04/2e6 =2.e-8 s using s = ½ a t^2 0.01 = 0.5 *{ (σ*1.6e-19/8.854e-12) – 1.67e-27*9.8}(2.e-8)²/1.67e-27 σ = 4.6e-6 c/m^2 =======================

Alycia Zemlak

Determining the velocity of a charged particle physics help!?

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