Find a nonzero vector parallel to the line of intersection of the two planes -(3x+3y+z) = -1 and 3x+2y+3z = 2.?
I am looking to find a nonzero vector that is parallel to the line of intersection between the two planes represented by the equations -(3x + 3y + z) = -1 and 3x + 2y + 3z = 2. Could someone assist me in determining this vector? Thank you!
1 Answers
Feb 22, 2025
The cross product of the normal vectors of the two planes will be parallel to the line of intersection.
(3, 3, 1) x (3, 2, 2) = (7, -6, -3)
Using one of the many cross product calculators on the web.
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