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Find q when 22.0 g of water is heated from 39 degrees Celsius to 100 degrees Celsius?

i need the answers in Joules

1 Answers

T1 = 39 + 273.15 K =312.15Kt2 = 100 + 273.15 = 373.15K q = m (t2-t1) sq = 22.0g ( 373.15K - 312.15K )4.186 joule/gram °Cq= 22.0g(61) 4.186 joule/gram °Cq = 5617.612 J... Show More

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