Find q when 22.0 g of water is heated from 39 degrees Celsius to 100 degrees Celsius?
What is the amount of heat energy (q) required to heat 22.0 grams of water from 39 degrees Celsius to 100 degrees Celsius? Please provide the answer in Joules.
1 Answers
Jan 14, 2025
T1 = 39 + 273.15 K =312.15K
t2 = 100 + 273.15 = 373.15K
q = m (t2-t1) s
q = 22.0g ( 373.15K - 312.15K )4.186 joule/gram °C
q= 22.0g(61) 4.186 joule/gram °C
q = 5617.612 J
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