FInd the Torque? …….. please help?

Question

A machinist is using a wrench to loosen a nut. The wrench is 25.0 cm long, and he exerts a force of 17.0 N at an angle of 37 degrees with respect to the handle.

What is the magnitude of the torque exerted by the machinist about the center of the nut?

What is the maximum torque he could exert with this force?

How should the force mentioned in part (2) be oriented?

The force is directed into the page.
The force is directed out of the page.
The force is perpendicular to the wrench.
The force is parallel to the wrench.

Additionally, three forces are applied to a wheel with a radius of 0.350 m, as shown in the figure. One force is perpendicular to the rim, one is tangent to it, and the other makes a 40.0-degree angle with the radius. The values of the forces are as follows: the perpendicular force to the rim is 11.9 N, the force making a 40-degree angle is 14.6 N, and the tangential force is 8.50 N. 
What is the magnitude of the net torque on the wheel due to these three forces, measured about an axis perpendicular to the wheel and passing through its center?

Anonymous · Accepted Answer

1) Torque = force . perpendicular distance = 17 . 0.25 . sin 37˚   = 2.56 Nm

2) Max torque would be 17 . 0.25  =  4.25 Nm

3) The force should be perpendicular to the wrench.

Without the diagram, I can’t do the next bit… too complex.
Sorry.

Anonymous

FInd the Torque? …….. please help?

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