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Oswald Hills

Feb 20, 2025

How do I calculate the average molar bond enthalpy of the carbon-bromine bond in CBr4 molecule.?

I have ∆Hº(Br(g)) = 111.9 kJ/mol , (C(g)) = 716.7 kJ/mol and (CBr4(g)) = 29.4 kJ/molI need to calculate the average molar bond enthalpy of the carbon-bromine bond in the CBr4 molecule
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M
∆Hrxn = ∆Hf[products]-∆Hf[reactants] ∆Hrxn = [(111.9)(4)+(716.4)]-[29.4]∆Hrxn = 1134.9divide by 4 because of stoichiometric ratios= 283.7 KJ*mol-1... Show More
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M
Mia is right, but just to clarify, you divide by 4 because you're looking for the AVERAGE molar bond enthalpy. ∆H(bond C-Br) = ∆Hrxn / 4Remember that the CBr4 molecule looks like this: Br I Br - C - Br I Br... Show More
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M
get a weighed pattern divide through Mr to get moles Burn this and locate out the potential of the pattern Divide this through form of moles to locate it for a million mole Divide through 5 to furnish one mole of Br-F bond... Show More
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