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How many molecules of sulfur trioxide are in 78.0 grams?

How can I calculate the number of molecules of sulfur trioxide (SO₃) contained in 78.0 grams?

1 Answers

Molar mass SO3 = 32.066+(15.99*3) = 80.036g/mol

78.0/80.036*6.022*10^23 = 5.86*10^23 molecules.

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