Carminic acid, a naturally occurring red pigment extracted from the cochineal insect, contains only carbon, hy?
Carminic acid, a naturally occurring red pigment extracted from the cochineal insect, is composed of carbon, hydrogen, and oxygen. It was commonly used as a dye in the first half of the nineteenth century and has a composition of 53.66% carbon and 4.09% hydrogen by mass. In a titration experiment, 18.02 mL of 0.0406 M NaOH was required to neutralize 0.3602 g of carminic acid. Assuming that there is only one acidic hydrogen per molecule, what is the molecular formula of carminic acid?
1 Answers
Use the titration to determine the MM of Carminic Acid.
(0.01802L)(0.0406M/L) = 0.0007316 moles NaOH
Assuming 1 acidic H per molecule, 0.3602g represents 0.0007316 moles of Carminic Acid.
Your MM of Carminic Acid is: 0.3602g/0.0007316moles = 492.337
The percentage of O must be 100.00 – (53.66 + 4.09) = 42.25
Change these to weight fractions by dividing each by 100.
C = 0.5366w/f H = 0.0409w/f O = 0.4225w/f
Multiply the MM of Carminic Acid by the w/f of each element then divide that by the MM of that same element.
For C: (492.337)(0.5366)/12.01115 = 21.995 round to 22
For H: (492.337)(0.0409)/1.00797 = 19.977 round to 20
For O: (492.337)(0.4225)/ 15.9994 = 13.001 round to 13
Your EMPIRICAL FORMULA is C22H20O13
Ideed, that is the correct formula for Carminic Acid.
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