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how would you do the cube root of 64 WITHOUT calculator?

math homework, appreciate help!

10 Answers

knowing that 64 = 8*8 and that the cube root of 8 = 2, i’d say the cube root of 64 = 2*2 = 4... Show More
You factor it out to primes:2*2*2*2*2*2 = 64If you need the square root you would divide it into two sets: (2*2*2)(2*2*2)=8×8=64.If you need the cube root you just divide it into three sets: (2*2)(2*2)(2*2)=4*4*4=64The same thing could be done for sixth root.So four is your answer, just through a few more examples up there.... Show More
after a while you know this from problems you have done. so remember cube root of 64 = 4 4 * 4 * 4 = 64... Show More
Just factorize it and get the answer64 = 2^6taking cube root => dividing power by 3 Therefore the answer is 2^2 = 4.... Show More
Look at the prime factorization of 64:64 = (2 x 2) x (2 x 2) x (2 x 2)The terms can be associated into three identical groups, henceCubeRoot(64) = (2 x 2) = 4... Show More
factor out 6464 = 8(8) = 2(4)(2)(4) = 4(4)(4)so, cube root of 64 = cube root of [4(4)(4)] = 4hope this helps... Show More
Not that 4*4=16 and 16*4=64. So, 4*4*4 = 16*4 = 64. Thus, the cube root of 64 is 4.... Show More
The long form solving of a cube root begins with the knowledge of a few basic cube roots including “64”.I’m not sure what your teacher is looking for but you could demonstrate a trial and error approach: Attempt 1: 3*3*3=27Attempt 2: 5*5*5=125Attempt 3: 4*4*4=64 Success!As far as I know, long form cube roots requires a memorized set of the basic cubes of 2,3,4,5,6,7,8 and 9. Getting the cube of 65 for example starts with a knowledge that 4 cubed is 64. 4. 3/———– / 65 -64 ——- 1.000The next decimal would be a value of x that would make the next equation less than 1000 for:(4^2 *300 + 4*30 * X+X^2 ) * Xin this case X = 0So the solution is tending towards 4.0_ _ _Eventually, you will get 4.02 using this method. But as you can see, I needed to know off the start that 4 was the cube of 64. This can only be “PROVEN” via the forwards of:4*4=1616*4 = 64.... Show More

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