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Parallel Axis Theorem?

Suppose a uniform slender rod has length and mass . The moment of inertia of the rod about about an axis that is perpendicular to the rod and that passes through its center of mass is given by . Find , the moment of inertia of the rod with respect to a parallel axis through one end of the rod.Express I(end)in terms of m and L
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Everardo Feil

Feb 20, 2025

Parallel axis theorem:Moment of inertia about arbitrary axis =Moment of inertia about center of mass+(mass)(distance between cm and axis)^2They give you the moment about CM (or you can look it up) then just add (m)(L/2)^2 to that.... Show More
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Everardo Feil

Feb 20, 2025

The M.I of a cube about an axis passing through the center of any two faces is ma² / 6 where a is the side of the cube and m is the mass of the cube. An edge of the cube is at a distance of (√2) / 2 of the side a . By parallel axis theorm The M.I about the edge of the cube is ma² / 6 + m [(√2)a / 2] ² = (2/3) ma ²... Show More
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Everardo Feil

Feb 20, 2025

To make it easier, you add the equation they gave you, which for me was (1/12)m(L^2) and add it to (m)(L/2)^2. This results in (1/3)m(L^2)... Show More
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