Elissa O'Keefe V
Oct 10, 2024
physics: A 27-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire. (a) What horizontal force woul?
A 27-kg chandelier hangs from the ceiling on a vertical wire that is 4.0 meters long.
(a) What horizontal force is required to displace the chandelier 0.15 meters to one side from its original vertical position?
(b) What will be the resulting tension in the wire?
3 Answers
arctan (0.15/4) = 2.15°
Weight = 27*9.8 = 264.6 N
Horizontal force is 246.4 sin(2.15°) = 9.24 N
Tension is sqrt(264.6² + 9.24²) = 264.8 N
Fy = Tcos(theta) = mg Fx = Tsin(theta) 3.58sin(theta) = 0.1m => theta = a million.60 ranges a. What horizontal stress could be mandatory to displace its place 0.10 m to one ingredient? Fx/Fy = (Tsin(theta))/(Tcos(theta)) = tan(theta) Fy = mg => Fx = mgtan(theta) = (30.7)(9.80 one)tan(a million.60) Fx = 8.4N b. what could be the stress in the cord? T = Fx/sin(theta) = 300N (2 s.f)
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