Physics Help!?
A boy ties a 58 g tennis ball to the end of a string that is 0.65 m long and whirls the ball in a horizontal circle above his head. The boy applies a force of 5.2 N on the string to keep the ball moving in the circle at a height of 1.7 m above the ground.
- Determine the speed of the ball.
- Describe the motion of the ball at the instant the string breaks.
- Explain the motion of the ball after the string breaks but before it hits the ground.
- Calculate how long it will take the ball to reach the ground after the string breaks.
- Determine how far the ball will travel horizontally before it hits the ground.
1 Answers
Jan 09, 2025
the angle with the vertical of the string is
5.2*cosθ=0.058*9.8
solve for θ
θ=acos(0.058*9.8/5.2)
θ=83.72 degrees
sinθ*5.2=m*v^2/r
solve for v
v=sqrt(r*sinθ*5.2/m)
we need r, which is the radius of the circle
r=0.65*sinθ
v=sinθ*sqrt(0.65*5.2/0.058)
v=7.59 m/s
When the string breaks, the ball becomes a free falling projectile starting form a height of 1.7m with vy=0 and vx=7.59 m/s
the time to impact is
t=sqrt(2*1.7/9.8)
0.589 s
the range is
7.59*0.589
4.47 m
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