Physics Frequency Question?

Question

Erin is late to physics class and is coming down the hall as the bells are ringing. There are two bells in the hall, one at the far end, and one in front of the classroom she is approaching. Each rings with a frequency of 500.0 Hz. As Erin comes down the hallway with a speed of 1.000 m/s toward the classroom, what frequency does she hear for each bell?Thanks!

Everardo Feil · Accepted Answer

It depends on the temperature, but assuming its room temperature…1. approaching bell Frequency2 = 500Hz (340m/s / 340m/s – 1m/s)F=498.5Hz2. Receding bellFrequency2 = 500Hz (340m/s / 340m/s +1m/s)F=501.5HzI hope this helps

Everardo Feil · Answer

A. Whatever is the length L of the pipe, its fundamental wavelength = 4L. (It’s 4L for a one-end-closed pipe, 2L for a both-ends-open pipe.) When the pipe is at the shortest resonant length (17 cm) the pipe fundamental wavelength (68 cm) and the fork wavelength are equal; when it is 51 cm long the 68-cm fork wavelength is 1/3 times the new pipe fundamental wavelength of 2.04 m. Closed pipes have the characteristic that they resonate at odd-integer divisors of the fundamental wavelength, or odd-integer multiples of the fundamental frequency. If a closed pipe has variable length, it resonates at any length that is equal to an odd-integer multiple of the fork wavelength divided by 4. So f = c/lambda1 = 340/(4*0.17) = 500 Hz. B. The next resonance occurs when the pipe length L = 5*68 cm/4 = 85 cm.

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Physics Frequency Question?

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