Physics Frequency Question?

Question

Erin is running late to her physics class and walking down the hallway as the bells are ringing. There are two bells in the hallway: one located at the far end and another right outside the classroom she is approaching. Both bells emit a frequency of 500.0 Hz. As Erin moves down the hallway at a speed of 1.000 m/s toward the classroom, what frequency does she perceive for each bell? Thank you!

Anonymous · Accepted Answer

It depends on the temperature, but assuming its room temperature…

1. approaching bell

Frequency2 = 500Hz (340m/s / 340m/s – 1m/s)

F=498.5Hz

2. Receding bell

Frequency2 = 500Hz (340m/s / 340m/s +1m/s)

F=501.5Hz

I hope this helps

Anonymous · Answer

A. Whatever is the length L of the pipe, its fundamental wavelength = 4L. (It’s 4L for a one-end-closed pipe, 2L for a both-ends-open pipe.) When the pipe is at the shortest resonant length (17 cm) the pipe fundamental wavelength (68 cm) and the fork wavelength are equal; when it is 51 cm long the 68-cm fork wavelength is 1/3 times the new pipe fundamental wavelength of 2.04 m. Closed pipes have the characteristic that they resonate at odd-integer divisors of the fundamental wavelength, or odd-integer multiples of the fundamental frequency. If a closed pipe has variable length, it resonates at any length that is equal to an odd-integer multiple of the fork wavelength divided by 4. So f = c/lambda1 = 340/(4*0.17) = 500 Hz. B. The next resonance occurs when the pipe length L = 5*68 cm/4 = 85 cm.

Anonymous

Physics Frequency Question?

2 Answers

AI-Powered Insights

Want to answer this question?

Categories

Tags

Related Questions