Physics question concerning a Modified Atwood Machine?

Question

On a modified Atwood machine (such as this one: http://spiff.rit.edu/classes/phys311/workshops/w5b), suppose the hanging mass is m2 = 254 g and the mass of the cart is m1 = 1205 g. Assume there is no friction in the system, and the system starts at rest. Use g = 9.81 m/s². 
a) What is the acceleration of the system? (Please provide the answer in m/s².) 
b) What is the tension in the string? (Please provide the answer in N.) 
c) If the track has a length of L = 2.02 m, what is vf, the speed of the cart just before it hits the barrier? (Please provide the answer in m/s.) 
I understand that you need to use the equation Vf² = Vi² + 2ad for the third question, but how do I find the answers to questions a and b?

Anonymous · Accepted Answer

Go herehttp://www.jick.net/~jess/hr/skept/Forces/node7.ht&hellip;Goodbye

Alexandria Schaden · Answer

Modified Atwood Machine

Anonymous · Answer

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Physics question concerning a Modified Atwood Machine?
On a modified atwood machine (such as this one: http://spiff.rit.edu/classes/phys311/workshops/w5b… suppose the hanging mass is m2 = 254 g and the mass of the cart is m1 = 1205 g. Assume there is no friction anywhere in the system, and the system starts at rest. Use…

Anonymous · Answer

On the planet of Earth,g=9.81m/sec^2 |m1-m2|g/(m1+m2)=a D=0.1=1/2(a)(1)^2,a=0.2 m/sec^2 |1.7-m2|g/1.7+m2=0.2 |1.7-m2|g=0.34+0.2m2 |1.7-m2|g=0.34+0.2m2 If 1.7g-m2g=0.34+0.2m2 m2=1.632kg If m2g-1.7g=0.34+0.2m2 m2=1.77kg God bless you.

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Physics question concerning a Modified Atwood Machine?

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