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Physics question…. help?

An archer shoots an arrow horizontally at a target 15 m away. The arrow is aimed directly at the center of the target, but it hits 48 cm lower. What was the initial speed of the arrow? (Neglect air resistance.)m/s

1 Answers

E
Everardo Feil

Feb 20, 2025

Find flight time: 0.48 = (1/2) g t^2t= sqr(2*0.48/9.8) = 0.31298 svx = x/t = 15/0.31298 = 47.926 m/svy = gt = -9.80.31298 = -3.067 m/sInitial speed of the arrow: v = sqr(vx^2 + vy^2)v = sqr(47.926^2+( -3.067^2)) = 48.02 m /s... Show More

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