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Please Help! Mastering Physics!?

1. What is the strength of the electric field at the position indicated by the dot in the figure?2. What is the direction of the electric field at the position indicated by the dot in the figure? Specify the direction as an angle above the horizontal line. http://session.masteringphysics.com/problemAsset/1…
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Everardo Feil

Feb 20, 2025

Electric field E1 due to charge at the top in the horizontal direction= kq/r^2= 9 x 10^9 x 1 x 10^-9 / (0.05)^2 N/C= 3600 N/C.Electric field E2 due to the lower charge making an angle θ with the horizontal= 9 x 10^9 x 1 x 10^-9 / [(0.05)^2 + (0.10)^2] = 720 N/CHorizontal component of E2= E2 cosθ = 720 * 5/√[5^2 + 10^2]= 322 N/CVertical component of E2= E2 sinθ= 720 * 10/√[5^2 + 10^2] = 644 N/CTotal horizontal component of net electric field, E= 3600 + 322 = 3922 N/CTotal vertical component of E= 644 N/CResultant E = √[(3922)^2 + (644)^2]= 3974.5 N/CIf it makes an angle α with the horizontal,tanα = 644/3922=> α = 9.32°.... Show More
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