What is the energy in joules of a photon whose frequency is 3.55 × 10^17 Hz?

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Please help me with this question: What is the energy in joules of a photon whose frequency is 3.55 × 10^17 Hz? I would appreciate a quick response. Thank you!

Adeline Goyette · Accepted Answer

The answer is $2.35 \times 10^{-16} \, \text{J}$.

Using the formula:

E = hv

This equation states that the energy of a particle of light (E), known as a photon, is proportional to its frequency (v), by a constant factor (h, the Planck constant, $6.626 \times 10^{-34} \, \text{J s}$). This implies that photons with low frequencies, such as radio waves, possess lower energies than photons with high frequencies, such as X-rays.

Solution:

E = (6.626 \times 10^{-34} \, \text{J s}) \times (3.55 \times 10^{17} \, \text{Hz})

E = 2.35 \times 10^{-16} \, \text{J}

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Hermina Ferry

What is the energy in joules of a photon whose frequency is 3.55 × 10^17 Hz?

1 Answers

E = hv

E = (6.626 \times 10^{-34} \, \text{J s}) \times (3.55 \times 10^{17} \, \text{Hz})

E = 2.35 \times 10^{-16} \, \text{J}

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