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Probability algebra 2 question?

The police department is keeping track of distracted drivers and accidents. They have found that if a driver is distracted, the driver has a 30% chance of being in an accident. If the driver is not distracted, the driver has a 2% chance of being in an accident. The probability of a driver being distracted is 10%. If needed, create a tree diagram on a separate piece of paper. Then use the diagram to answer the questions. a. What is the probability a driver will be in an accident? Explain. b. What is the probability that a driver who was in an accident was distracted? ExplainCan anyone walk me step by step through this? I’m really having trouble with this unit and would really appreciate it!

2 Answers

First draw a probability tree. Start with branches for distracted and not distracted. Then branch off of there for accident or no accident. Be sure to include the percentages for each branch, as a decimal:…………… …………. / Accident (0.30)../ Distracted (0.10) ./ …………. …………. No accident (0.70)/. …………… …………… / Accident (0.02).. Not distracted (0.90) ………………. …………… No accident (0.98)PART A:There are two cases.Driver was distracted (0.10) and had an accident (0.30)0.10 x 0.30 = 0.03 Driver was not distracted (0.90) and had an accident (0.02)0.90 x 0.02 = 0.018Add these together:0.03 + 0.018= 0.048Answer:4.8%PART B:This is a little trickier. Here we can ignore the cases where the driver did not have an accident. We have only two cases, as we figured out in part A.0.03 –> accident happened while distracted0.018 –> accident happened while not distractedWe want the first case (accident while distracted) compared to the total probability of any accident (two cases added together).So basically it is:0.030.03 + 0.018We already figured out the denominator from part A: 0.030.048That reduces to:30 .. 5— = — = 0.62548 .. 8Answer:62.5% a driver that was in an accident was distracted... Show More

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