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Alize Kuhn

Feb 20, 2025

Solve 2×2 + 5x + 5 = 0. Round solutions to the nearest hundredth.?

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Lavinia Carroll

Feb 20, 2025

No real solutions 2x2 + 5x + 5 = 0x^2 + 5/2 x + 5/2 = 0D = (5/2)^2 - 4(1)(5/2)= 25/4 - 20/2 = 25/4 - 40/4 = - 15/4 < 0 ====> complex roots... Show More
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Lavinia Carroll

Feb 20, 2025

I would rather have the solutions remain in radical form, but sure. 2x² + 5x + 5 = 0The best way to solve this, especially when you know the solution will be irrational at best, is to use quadratic formula:x = [ -b ± √(b² - 4ac)] / (2a)Using a = 2, b = 5, and c = 5, we get:x = [ -5 ± √(5² - 4(2)(5))] / (2*2)x = [ -5 ± √(25 - 40)] / 4x = [ -5 ± √(-15)] / 4With a negative number under the radical, we can stop here and say there are no real solutions.... Show More
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