Mrs. Joy Prosacco
Dec 26, 2024
Solve 2×2 + 5x + 5 = 0. Round solutions to the nearest hundredth.?
Solve the equation (2x^2 + 5x + 5 = 0). Please round the solutions to the nearest hundredth. What are the solutions?
2 Answers
No real solutions
2x2 + 5x + 5 = 0
x^2 + 5/2 x + 5/2 = 0
D = (5/2)^2 - 4(1)(5/2)
= 25/4 - 20/2 = 25/4 - 40/4 = - 15/4 < 0 ====> complex rootsJan 05, 2025
I would rather have the solutions remain in radical form, but sure.
2x² + 5x + 5 = 0
The best way to solve this, especially when you know the solution will be irrational at best, is to use quadratic formula:
x = [ -b ± √(b² - 4ac)] / (2a)
Using a = 2, b = 5, and c = 5, we get:
x = [ -5 ± √(5² - 4(2)(5))] / (2*2)
x = [ -5 ± √(25 - 40)] / 4
x = [ -5 ± √(-15)] / 4
With a negative number under the radical, we can stop here and say there are no real solutions.
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