The equilibrium system between hydrogen gas, bromine gas, and hydrogen bromide gas is given. H2(g) + Br2 (g) 2HBr(g).?
I am studying the equilibrium system involving hydrogen gas, bromine gas, and hydrogen bromide gas, represented by the reaction: H2(g) + Br2(g) ⇌ 2HBr(g). However, I mistakenly derived the reaction as 2HBr(g) ⇌ H2(g) + Br(g). Can someone help me understand what I’m missing or where I went wrong in my approach? Thank you!
1 Answers
Feb 04, 2025
Bromine gas exists as Br₂ molecules, but not Br atoms. Hence, it is Br₂(g) instead of Br gas.
Hence, the equation should be :
H₂(g) + Br₂(g) ⇌ 2HBr(g)
OR: 2HBr(g) ⇌ H₂(g) + Br₂(g)
Both of the above equations are correct. However, someone only accepts the first equation which follows the order of giving components, i.e. hydrogen gas, bromine gas and then hydrogen bromide gas.
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