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The two members used in the construction of an aircraft fuselage are joined together using a 30° fish-mouth weld. Determine the

This question is incomplete because it lacks the required diagram of the fuselage. Please find attached to this answer the appropriate diagram.

3 Answers

A
Abbie Toy

Feb 20, 2025

This question is incomplete because it lacks the required diagram of the fuselage. Please find attached to this answer the appropriate diagram.The average normal stress on the plane of each weld = 66.7 psiThe average shear stress on the plane of each weld = 115.5 psiExplanation: From the question, we are told that two members are joined together.From the diagram we see 800lb.Since there are 2 members = 800lb/2= 400lba) The formula for average nor umal stress on the plane of each weld = Force (in Newton)/ Cross sectional area (in inches) From the question, we are assuming that the horizontal force = 400lbWe are given an angle of 30°Therefore, the resultant force in Newton = F sin θ= 400 sin 30 = 200lbCross sectional area = A/sin θ= 1 × 1.5/ sin 30= 3 in²The average normal stress on the plane of each weld is calculated as:200lb/3 in²= 66.7lb/in² or 66.7 psib) The average shear stress on the plane of each weld = Force (in Newton)/ Cross sectional area (in inches)Resultant force =  F cos θ= 400 cos 30 = 346.41016151lbApproximately = 346.41lbCrossectional area = 3 in²The average normal stress on the plane of each weld is calculated as:346.4lb/3 in²= 115.47Ib/in²Approximately = 115.5Ib/in²Therefore, The average normal stress on the plane of each weld = 66.7 psiThe average shear stress on the plane of each weld = 115.5 psi... Show More
A
Abbie Toy

Feb 20, 2025

Dmaybe? i’m one of the dumbest girls out there so not to sure, i think it’s d tho... Show More
A
Abbie Toy

Feb 20, 2025

the correct answer, according to e2020, is the second choice there is an occluded front in region a and a cold front in region b.... Show More

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