three 240 ohm resistors can be connected together in 4 different ways..?

Question

How can three 240-ohm resistors be connected in four different configurations, utilizing combinations of series and parallel circuits? Could you explain these four configurations and calculate the net resistance for each arrangement?

Anonymous · Accepted Answer

240/3 = 80&Omega; (all 3 in parallel)240&times;3 = 720&Omega; (all 3 in series)240/2+240 = 360&Omega; (2 in parallel with third in series)240&times;2 = 480480&times;240/(240+480) = 160&Omega; (2 in series all in parallel with third).

Anonymous · Answer

240 Ohm Resistor

Adeline Price · Answer

Right, you can have them connected in straight off series (3 in a row) giving R=240+240+240

—-===—–===—-===–

Or 3 in parallel in which case

1/R = 1/240 + 1/240 + 1/240

—===—

–===–/

-===-/

Or you could have two in parallel, which is then attached to another.

Giving R=240+r where 1/r = 1/240+1/240

–===—-===–

-===-/

Finally you could have a situation where there’s 2 in series, in parallel with another

This would give 1/R = 1/240 + 1/480

—===–===—-

—–===——-/

Do the maths 🙂

Anonymous · Answer

All 4 in series, 2 in series with 2 in parallel in series, 1 in series with 3 in parallel, all 4 in parallel. If you can think of any other possible configurations, you tell me! I say 4.

Anonymous · Answer

all parallel, all series, two in series parallel with another, two in parallel in series with another.
equivalent resistance in parallel = 1/R1 + 1/Rn (add reciprocals)
equivalent resistance in series = R1+Rn (just add’em up)

Laurine Denesik

three 240 ohm resistors can be connected together in 4 different ways..?

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