Ronny Kunde
Feb 09, 2025
TOUGH ORGANIC CHEMISTRY PROBLEM!! (ACID/BASE 3 problem Q)?
Complete the equations for the following equilibria and calculate Keq, ensuring the Keq expression includes [H2O]. Express Keq in proper scientific notation.
Given species and their pKa values:
- NH3 (Ammonia): pKa = 35
- NH4+ (Ammonium): pKa = 9.25
- H2O (Water): pKa = 15.74
- H3O+ (Hydronium): pKa = -1.74
(A) Ammonia acting as a base reacts with water (acting as an acid):
NH3 + H2O → ?
Keq = ?
(B) Ammonia acting as an acid reacts with water (acting as a base):
NH3 + H2O → ?
Keq = ?
(C) Which of these reactions is more significant in an aqueous solution of ammonia: reaction A or B?
I’m having trouble solving this organic chemistry problem regarding acid-base equilibria. Any help would be greatly appreciated—thank you!
2 Answers
A) NH3 +H2O <–> NH4+ (+) OH-
Log(Keq) = pKa [B] – pKa [A] … therefore Keq = 10^ (pKa [B]- pKa [A])
Keq = 10^ (pKa [B]- pKa [A])
Keq = 10^ (9.25 – 15.74)
Keq = 3.2×10^-7
B) NH3 + H20 <–> NH2- (+) H30+
Keq = 10^ (-1.74 – 35)
Keq = 1.8×10^-37
C) The answer is “A”.
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