TOUGH ORGANIC CHEMISTRY PROBLEM!! (ACID/BASE 3 problem Q)?

Question

Complete the equations for the following equillibria and calculate Keq where the Keq expression includes [H2O]. Be sure to enter Keq in proper scientific notation. Species: NH3 pKa:35Species: NH4+ pKa:9.25 Species: H2O pKa:15.74Species: H30+ pKa:-1.74(A) Ammonia (acting as a base) reacts with water (acting as an acid)NH3 + H2O  Keq=?(B)Ammonia (acting as an acid) reacts with water (acting as an base)NH3 + H2O  Keq=?(C) Which of these reactions is more important in an aqueous solution of ammonia. A or B? Having lots of issues on this organic Hw prob. Any help is appreciated thank you!!

Bernhard White · Accepted Answer

A) NH3 +H2O  NH4+ (+) OH-Log(Keq) = pKa [B] – pKa [A] … therefore Keq = 10^ (pKa [B]- pKa [A])Keq = 10^ (pKa [B]- pKa [A])Keq = 10^ (9.25 – 15.74)Keq = 3.2×10^-7 B) NH3 + H20  NH2- (+) H30+Keq = 10^ (-1.74 – 35)Keq = 1.8×10^-37C) The answer is “A”.

Bernhard White · Answer

I am also in twelfth and i have the same hindrance dude….. However are attempting learning them by writing and practising… Hope it’s going to work…’cos i’m doing the identical too…. Pleasant of good fortune…

Mr. Ellis Hintz

TOUGH ORGANIC CHEMISTRY PROBLEM!! (ACID/BASE 3 problem Q)?

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