What are the coordinates of the vertex for f(x) = 3×2 + 6x + 3?
What are the coordinates of the vertex for the quadratic function ( f(x) = 3x^2 + 6x + 3 )?
3 Answers
For f(x) = ax^2 + bx + c
x- coordinate of the vertex = -b/2a
y- coordinate of the vertex = f(x) = f(-b/2a)
Here,
f(x) = 3x^2 + 6x + 3
x-coordinate = -6/2*3 = -1
y-coordinate = f(-1) = 3(-1)^2 + 6(-1) + 3 = 3-6+3 = 0
Thus coordinates => (-1, 0)
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