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Miss Alice Doyle

Feb 20, 2025

What are the coordinates of the vertex for f(x) = 3×2 + 6x + 3?

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3 Answers

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Tiana Kshlerin

Feb 20, 2025

For f(x) = ax^2 + bx + cx- coordinate of the vertex = -b/2a y- coordinate of the vertex = f(x) = f(-b/2a)Here,f(x) = 3x^2 + 6x + 3x-coordinate = -6/2*3 = -1y-coordinate = f(-1) = 3(-1)^2 + 6(-1) + 3 = 3-6+3 = 0 Thus coordinates => (-1, 0)... Show More
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Tiana Kshlerin

Feb 20, 2025

f(x)=y=3(x^2+2x+1)=3(x+1)^2The vertex is where x=-1 so y=0... Show More
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Tiana Kshlerin

Feb 20, 2025

3x^2 + 6x + 33(x^2 + 2x + 1)3(x + 1)(x + 1)Now let's sub it back into the equation and make f(x) = 0.3(x + 1)(x + 1) = 0x = -1Let's make x = 0 to get the y-intercept and you'll get:y = 3Vertex = (-1, 3)... Show More
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