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A

Anonymous

Dec 15, 2024

Wat are the equilibrium concentrations of pb2+ and f- in a saturated solution

What are the equilibrium concentrations of Pb²⁺ and F⁻ in a saturated solution of lead fluoride?

The problem states: "What are the equilibrium concentrations of Pb²⁺ and F⁻ in a saturated solution of lead fluoride if the Ksp of PbF₂ is 3.2 × 10⁻⁸?"

Here's my approach: I used the formula (x)(2x)² = 3.2 × 10⁻⁸, which simplifies to 4x³ = 3.2 × 10⁻⁸. Solving for x, I found x = 0.002, which is the correct concentration of Pb²⁺.

However, I’m having trouble determining the concentration of F⁻. Could someone guide me through the steps to calculate it? Thank you!

1 Answers

A
Anonymous

Jan 05, 2025

If 0.002 mole/L of PbF2 dissolves, the concentration of Pb^+2 will be 0.002 mole/L and the concentration of F^-1 must be 0.004 mole/L (2 x 0.002 = 0.004)

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