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A

Anonymous

Nov 24, 2024

What is her speed at the bottom of the slope?

A cyclist is coasting at a speed of 11 m/s when she begins to descend a slope that is 410 meters long and 30 meters high. The combined mass of the cyclist and her bicycle is 70 kg. Throughout the descent, a steady drag force of 15 N due to air resistance acts on her. What is her speed at the bottom of the slope?

2 Answers

A
Anonymous

Feb 14, 2025

Θ = arcsin(30/410) = 4.2º

weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

friction upslope = 15 N

net downslope force = 35.2 N, so

net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

Now use Torricelli's equation:

v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

v = 23 m/s

Hope this helps!

A
Anonymous

Feb 17, 2025

A steady 15N drag force due to air resistance acts on her --that isn;t how it works

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