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What is her speed at the bottom of the slope?

A cyclist is coasting at 11m/s when she starts down a 410m long slope that is 30 m high. The cyclist and her bicycle have a combined mass of 70 kg. A steady 15N drag force due to air resistance acts on her as she coasts all the way to the bottom.

2 Answers

K
Kian Lynch

Feb 20, 2025

Θ = arcsin(30/410) = 4.2ºweight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 Nfriction upslope = 15 Nnet downslope force = 35.2 N, sonet downslope acceleration = 35.2N / 70kg = 0.50 m/s²Now use Torricelli's equation:v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²v = 23 m/sHope this helps!... Show More
K
Kian Lynch

Feb 20, 2025

A steady 15N drag force due to air resistance acts on her --that isn;t how it works... Show More

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