What is the volume of 5.60 g of O2 at 7.78 atm and 415K?
What gas law should I use to solve this problem? Can you explain the process step by step? I missed the class where this was covered, and the textbook examples aren’t detailed enough to help me understand.
2 Answers
Use PV = nRT, where P is pressure, V is volume, n is moles, R is gas constant, T is temp in K
so rearrange the equation to read V = (nRT) / P
plug in what you know.
Calculae the mol of O2 in 5.60 g of O2 n = m / M 5.60 g / 32 g/mol = 0.175 mol
V = (0.175 x 0.08205 x 415) / 7.78 V = 0.769 LRelated Questions
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