What is the wavelength of light having a frequency of 4.8X10^14 s^-1 (c=3.0X10^8m/s)?
What are the steps to calculate the wavelength of light with a frequency of 4.8 × 10¹⁴ s⁻¹, given that the speed of light (c) is 3.0 × 10⁸ m/s? Additionally, could you clarify what "c" represents in this context? Thank you in advance for your help—I'm preparing for my chemistry exam!
1 Answers
the general equation is v = f lambda
where v is speed in m/s, f is frequency in Hz (s^-1) and lambda is wavelength in m
but c is the speed of light
so
c - f lambda
3.0E8 = 4.8E14 *lambda
lambda = 6.25E-7 m or 625 nm
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