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Jakob Littel

Feb 20, 2025

A motorcycle daredevil is attempting to jump across as many buses as possible (see the drawing). The takeoff r?

A motorcycle daredevil is attempting to jump across as many buses as possible. The takeoff ramp makes an angle θ = 19.0° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The cyclist leaves the ramp with a speed of v = 34.0 m/s. What is the maximum number of buses over which the cyclist can jump?

1 Answers

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Hermina Ferry

Feb 20, 2025

Assuming the top of the ramp is at the same height as the buses.Select the upeard direction as positive and the top of the ramp as the origin.The vertical motion os the bus isy = -(1/2)gt^2 +34sin(19)*tWhen the motorcycle reaches the other ramp, the vertical height is 0, thus= -(1/2)gt^2 + 34sin(19)t Solving for t,t = 2.26 secDuring the 2.26 s, the motorcycle travels a horizontal distance ofd = 34cos(19)2.26d = 72.65 mThe number of buses the motorcycle jumps over isn = 72.65/2.74n = 26 buses... Show More

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