A motorcycle daredevil is attempting to jump across as many buses as possible (see the drawing). The takeoff r?
A motorcycle daredevil is attempting to jump across as many buses as possible. The takeoff ramp is angled at θ = 19.0° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, with each bus measuring 2.74 m in width. The cyclist leaves the ramp with a speed of v = 34.0 m/s. What is the maximum number of buses that the cyclist can jump over?
1 Answers
Assuming the top of the ramp is at the same height as the buses.
Select the upeard direction as positive and the top of the ramp as the origin.
The vertical motion os the bus is
y = -(1/2)gt^2 +34sin(19)*t
When the motorcycle reaches the other ramp, the vertical height is 0, thus
= -(1/2)gt^2 + 34sin(19)t
Solving for t,
t = 2.26 sec
During the 2.26 s, the motorcycle travels a horizontal distance of
d = 34cos(19)2.26
d = 72.65 m
The number of buses the motorcycle jumps over is
n = 72.65/2.74
n = 26 buses
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