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Jakob Littel

Feb 20, 2025

A propeller is modeled as five identical uniform rods extending radially from its axis. The length and mass..?

of each rod are 0.757 m and 2.63 kg, respectively. When the propellor rotates at 529 rpm (revolutions per minute), what is its rotational kinetic energy?
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Hermina Ferry

Feb 20, 2025

KErot = ½Iω²For each, I = mL²/3 = 2.63kg * (0.757m)² / 3 = 0.502 kg·m² ω = 529rev/min 2πrads/rev 1min/60s = 55.4 rad/sKErot = ½ * 5 * 0.502kg·m² * (55.4rad/s)² = 3850 J... Show More
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