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Alycia Zemlak

Feb 20, 2025

Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 × 10-17.

Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 × 10-17.
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When the salt AgI dissolves in water it dissociates as follows;AgI ---> Ag⁺ + I⁻molar solubility is the number of moles that are dissolved in 1 L of solution.If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.the formula for solubility product constant - ksp of AgI is given below ksp = [Ag⁺][I⁻]ksp = (x)(x)ksp = 8.51 x 10⁻¹⁷ therefore,x² = 8.51 x 10⁻¹⁷x = 9.22 x 10⁻⁹since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M... Show More
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Olá. porque a reação na temperatura é muito rapida a do copo : )... Show More
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answer: cellular respiration takes in food and uses it to create atp, a chemical which the cell uses for energy. usually, this process uses oxygen, and is called aerobic respiration. it has four stages known as glycolysis, link reaction, the krebs cycle, and the electron transport chain.... Show More
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