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Find the plane determined by the intersecting lines (Calculus III Help)?

Hello,need some help with this problem. my math is not coming out. PLEASE SHOW STEPS! Thanks so much for your help. Find the plane determined by the intersecting lines L1 : x= -1 + t y= 2+t z = 1-t L2: x= 1-4s y=1+2s z=2-2sAnswer: y+z=3Thanks again!
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Dr. Juanita Wolff

Feb 20, 2025

x=-1+ty=2+tz=1-t ——–x=1-4sy=1+2sz=2-2s———--1+t=1-4s =>t=-4s+22+t=1+2s4-4s=1+2s6s=3 =>s=1/2 =>t=0 verify:1-t=2-2s1-0=2-11=1 truethe point of intersection is (-1,2,1)———–the parametric form of the lines are:L1=(-1,2,1)+t(1,1,-1)L2=(1,1,2)+s(-4,2,-2)take the cross product of:<1,1,-1>*<-4,2,-2> = <0,6,6>as it passes through (-1,2,1) then:0(x+1)+6(y-2)+6(z-1)=06y+6z=18y+z=3... Show More
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Dr. Juanita Wolff

Feb 20, 2025

Can you check your formula – this is not soluble.... Show More
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