For the reaction 2 NH3 + CH3OH ! products , how much CH3OH is needed to react with 93.5 g of NH3?
For the reaction 2 NH3 + CH3OH → products, how much CH3OH is needed to react with 93.5 g of NH3?
Could someone please explain how to solve this problem? The multiple-choice answers are as follows: - 46.8 mol - 88.1 mol - 2.75 mol - 3.32 mol - 11.3 mol - 5.50 mol - 1.31 mol
1 Answers
Nov 23, 2024
MW: NH3 = 17, CH3OH = 32
moles of NH3 = 93.5/17 = 5.5
according to the equation, 1/2 mol methanol reacts with each mol of ammonia, so it would take 5.5/2 or 2.75 mol.
answer is no 3.
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