if 3x^2 – 2x 7 = 0, then ( x – 1/3 ) ^2 = ?

Question

how do i get the answer

Jonathon Rolfson · Accepted Answer

3x² – 2x + 7 = 03x² – 2x = – 7 x² – 2/3x = – 7/3x² – 1/3x = – 7/3 + (1/3)²x² – 1/3x = – 21/9 + 1/9(x – 1/3)² = – 20/9Answer: (x – 1/3)² = – 20/9

Jonathon Rolfson · Answer

I agree with Como.You should separate it into 3 times (x^2 – (2/3)x + (7/3) = 0Because it can be done using the quadratic formula now that it is separated into x square x and a number, which are respectively a, b, and c. And then after the quadratic formula, you can multiply the answers you get by 3.

Jonathon Rolfson · Answer

3x 2 2x 7

Jonathon Rolfson · Answer

3x 2-2x 7 0

Jonathon Rolfson · Answer

3x² – 2x + 7 = 03(x² – (2/3)x + 7/3) = 0x² – (2/3)x + 7/3 = 0x² – (2/3)x + 1/9 = 1/9 – 7/3(x – 1/3)² = – 20/9

Jonathon Rolfson · Answer

https://shorturl.im/RDqKIx = (2 +/- i*sqrt80)/6. x = (1 +/- i*sqrt20)/3. (x – (1/3))^2 = (1/3 + i*sqrt(20)/3 – 1/3)^2 = -20/9. (x – (1/3))^2 = (1/3 – i*sqrt(20)/3 – 1/3)^2 = -20/9. Answer: -20/9 or -2 2/9. -John

Jonathon Rolfson · Answer

first, find x. Quadratic formula would probably be easiest.(2 + / – sqrt (4 – 84)) / 6(2 + / – sqrt (-80)) / 6(2 + / – 4i(sqrt5) / 6x=(1 + 2i(sqrt5)) / 3 OR (1 – 2i(sqrt5)) / 3((1 + 2i(sqrt5)) / 3 – 1/3)^2 = (((2i(sqrt5))/3)^2) = -20/9((1 – 2i(sqrt5))/3 – 1/3)^2 = (((-2i(sqrt5))/3)^2) = -20/9-20/9. Man, that was a workout!BTW Jon Agruda got the right answer . . . but I question his methods a little bit, looks like he randomly put a (1/3)^2 in there about the fourth line. also, last step, he says that x^2 – (1/3)x = (x-1/3)^2, that is not true. But then again, he is a top contributor so I’m not sure, but I know my methodology is right.

Jonathon Rolfson · Answer

What is 2x 7, did you miss a sign?

Natalie Goodwin

if 3x^2 – 2x 7 = 0, then ( x – 1/3 ) ^2 = ?

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