If 5.0 moles of C3H8 react, how many molecules of water are formed?

Question

If 5.0 moles of propane (C3H8) undergo complete combustion, how many molecules of water (H2O) are produced as a result of the reaction? Could you please provide a detailed explanation of the stoichiometry involved in this calculation?

Mr. Dion Kovacek · Accepted Answer

The reaction of propane with oxygen is C3H8 + 5 O2 —-> 3 CO2 + 4 H2O
Therefore for every atom of C3H8, four atoms of water are produced.
Therefore 5 moles of C3H8, 5 x 4 moles of water are produced
On the basis of Avogadro’s constant, 1 mole of water contains  6.02214129 x 10^23 molecules
Therefore 5 x 4 = 20 moles
20 moles of water contains 20 x 6.02214129 x 10^23 molecules
= 120.4428158 x 10^23 = 1.204428158 x 10^25 molecules of water

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Flo Predovic

If 5.0 moles of C3H8 react, how many molecules of water are formed?

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