In the steady state, what is the charge q of the capacitor? How much work W is done by the voltage source…?

Question

RC Circuit(see my drawing)______VVVV(R)____| || || || || =(capacitor)EMF || || ||_____/(switch)_____|In that steady state, the charge of the capacitor is not changing. In the steady state, what is the charge q of the capacitor?Express your answer in terms of any or all of EMF, R, and C.How much work W is done by the voltage source by the time the steady state is reached?I was unable to answer these two.

Jayce Wintheiser · Accepted Answer

The definition of capacitance is given by Q = V * C where q is the charge stored and C is the capacitance.So if the the emf is called V and if the capacitor is fully charged then there is no current flowing and the amount of charge in the capacitor is simply VCIn the second question there is a trick intended.Energy = Emf * Chargeso E= VQ= V * V * Q = V^2 CThis is the energy supplied by the battery. Some has gone into the capacitor and some has been lost in the form of heat in the resistor.( incidentally the energy IN the capacitor is 1/ C V^2 so half of the energy was lost in the resistor.)

Jayce Wintheiser · Answer

in case you recommend “stable-state” as that not extra cutting-edge would be flowing into it: The capacitor won’t straight away gain that situation. it is going to require a while till now that situation is finished, on the grounds that’s being charged exponentially and as a function of time.

Mr. Keeley Hilpert

In the steady state, what is the charge q of the capacitor? How much work W is done by the voltage source…?

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