Nicl3 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m nicl3 solution

Question

Nicl3 is a strong electrolyte. Please determine the concentration of each individual ion in a 0.450 m NiCl3 solution.

Anonymous · Accepted Answer

NiCl3 is a strong electrolyte. This means that when on solution it dissociates completely into ions. The dissociation reaction would be written as:NiCl3 = Ni3+ + Cl-The ratio of the ions and the compound are all 1 is to 1. Therefore, the concentration of the individual ions would be the same as the concentration of the compound at a certain volume.

Marcia Kertzmann · Answer

The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is [Ba2+] = 0.750 M[OH-]= 1.50 Mcalculationwrite the equation for dissociationthat is  Ba(OH)2  (s)→ Ba2+(aq)  + 2OH-(aq) by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750Mby use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of  OH- =0.750 M x2/1=1.50 M

Anonymous · Answer

= 0.3 M = 0.6 MExplanation:We can start wit the ioniation reaction:We have the ions and . Now, we can calculate the concentration of each ion:Concentration of In balanced reaction we have 1 mol of and 1 mol of , so, we have a 1:1 mol ratio, with this in mind:Concentration of In balanced reaction we have 1 mol of and 2 mol of , so, we have a 1:2 mol ratio, with this in mind:I hope it helps!

Anonymous · Answer

Answer : The concentration of each of the individual ions are, 0.6 M and 1.8 M .Explanation : Given,Concentration of solution = 0.6 MThe balanced chemical reaction will be :From the balanced chemical reaction we conclude that, 1 mole of dissociates to give 1 mole of and 3 moles of .So,The concentration of = The concentration of = 0.6 MThe concentration of =  3 × The concentration of = Therefore, the concentration of each of the individual ions are, 0.6 M and 1.8 M .

Anonymous · Answer

Answer; [Ba2+] = 0.550 M  [OH-] = 1.10 M Explanation;Each mol Ba(OH)2 releases 2 mol OH-  Ba(OH)2 > Ba2+ + 2OH-  Mole ratio; Ba(OH)2 :Ba2+ = 1 : 1[Ba2+] = 0.550 M  Mole ratio; Ba(OH)2: 2OH-  = 1 : 2= 2 × 0.550 = 1.10[OH-] = 1.10 M  This assumes complete ionization (dissociation) of Ba(OH)2.

Daphnee Nienow · Answer

[Ba^2+]= 0.400M[OH-]= 0.800MExplanation: Step 1: Data givenMolarity ofBa(OH)2 = 0.400 MBa(OH)2 is a strong electrolyte, so 100 % dissociationStep 2: The equationBa(OH)2 → Ba^2+ +  2OH-In 1 mol Ba(OH)2 we have 1 mol Ba^2+ and 2 moles OH-Step 3: Calculate the concentration[Ba^2+]= 1* 0.400 M = 0.400M[OH-]= 2*0.400 M = 0.800M

Dr. Clifton Kihn IV · Answer

A strong electrolyte is a solute that completely, or almost completely, ionizes or dissociates in a solution. Therefore, NiCl3 dissociates into ions completely. The dissociatio equation would be:NiCl3 ---> Ni3+ + 3Cl-1Threfore, the concentration of the ions would be 0.4 M Ni3+ and 1.2 M Cl-1.

Larue Gibson PhD · Answer

Conc. of K+ ions = 0.90 MCoc. of SO4∧-2 = 0.45 MExplanation:Data Given: Conc. of H2SO4 = 0.450As sulphoric acid is a strong electrolyte, it completely dissociate into ions.H2SO4 ⇆   2K+   +   SO4∧-2.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.                       K2SO4  :  K+                                          K2SO4  : SO4∧-2                           1      =     2                                                   1     =    1                      0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450 Result: Conc. of potassium ion will be 0.90M     Coc. of sulphate ions will be 0.45 M

Jarod Hudson · Answer

For the answer to the question above, I'll show the solutions for my answer.(0.800 M NiCl3) x (1 mol Ni^3+ / 1 mol NiCl3) = 0.800 M Ni^3+ (0.800 M NiCl3) x (3 mol Cl^- / 1 mol NiCl3) = 2.40 M Cl^-I hope my answer helped you. Have a nice day!

Golden Hansen III · Answer

Potassium sulfate or K₂SO₄ is a strong electrolyte which means that it will completely dissociate into ions when dissolved in water. The dissociation reaction is as follows:K₂SO₄ → 2K⁺ + SO₄²⁻ This means that the dissociation of 1 mol of K₂SO₄ solution will yield 2 moles of K⁺ and 1 mole of SO₄²⁻. Molarity is a measure of concentration defined as moles divided by the volume of solution. In this case, given that the volume is constant, from stoichiometry, the concentration of K⁺ ions would be twice of 0.600 M which is 1.200 M. On the other hand, the concentration of SO₄²⁻ is 0.600 M by stoichiometry.

Anonymous

Nicl3 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m nicl3 solution

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