A mass on a string of unknown length oscillates as a pendulum with period of 4.77 s.?

Question

A mass suspended on a string of unknown length oscillates as a pendulum with a period of 4.77 seconds. If the length of the string is doubled, what will be the new period? What will the period be if the length of the string is halved? Additionally, how does the period change if the amplitude is doubled?

Anonymous · Accepted Answer

Amplitude has no effect on the period of the pendulum, it will still take the same amount of time to complete one swing if the amplitude is made bigger, it will just move faster to swing the extra distance in the same time.
The equation governing period and length of a pendulum is 
T = 2π√(L/g), where g is the acceleration due to gravity. The important thing to note here is that if the acceleration due to gravity is held constant, the time period is proportional to the square root of the length.
So if the string length is doubled, the period increases by a factor of √2.
So the period of the new length is √2 x 4.77 s = 6.75 s.
And if the string length is halved, you need to divide 4.77 by √2 to get a time period of 3.37 s.

Anonymous · Answer

The equation for term is T = 2pi x sq. root of (l/g) wher l is the dimensions of the pendulum and g the acceleration by using gravity. T = 2 x 3.14 x squareroot(34/9.8) = 11.7 s 2) it is sparkling that c is your best option

Royal Zulauf

A mass on a string of unknown length oscillates as a pendulum with period of 4.77 s.?

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