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A potter is shaping a bowl on a potter’s wheel rotating at constant angular speed. The friction…?

A potter is shaping a bowl on a potter's wheel that is rotating at a constant angular speed. The total friction force between her hands and the clay is 1.5 N.

a) What is the torque exerted by the potter on the wheel, given that the diameter of the bowl is 12 cm?

b) How long would it take for the potter's wheel to stop if the only torque acting on it is due to the potter's hands? The initial angular velocity of the wheel is 1.6 rev/s, and the moment of inertia of the wheel and the bowl is 0.11 kg·m².

The textbook states that the answer to part a) is 9.0 x 10^-2 m·N and part b) is 12 seconds. Thank you for your assistance!

1 Answers

A
Anonymous

Feb 17, 2025

(a).

2 torque = F r

2 torque = (1.5)(0.12)

torque = 0.09 Nm

(b).

angular acceleration,

α = -torque/I

0 = ω + α t

0 = ω + (-torque/I) t

0 = (1.6 * 2π) + (-0.09/ 0.11) t

t = 12.2871 sec

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